Physics, asked by aveeranna132, 8 months ago

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Answered by kailashmeena123rm
12

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option (1)

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acceleration at equator

g_e = g - R {\omega_ \circ}^{2}    \:  \\

where R is radius of earth and g is acceleration due to gravity

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given body feel weightlessness

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g_e = 0 = g - R {\omega_ \circ}^{2}     \:  \\

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 \rightarrow \: g - R {\omega_ \circ}^{2}  = 0\\ {\omega_ \circ} =  \sqrt{ \frac{g}{R} }  \:  \\  \\  \\

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