Math, asked by kruthi72, 7 months ago

solve this question

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Answered by harishagarwal699

0

Answer:

3y^2-4x^2+3x

Step-by-step explanation:

i)(2y^2+3x-x^2)-(3x^2-y^2)

=2y^2+3x-x^2-3x^2+y^2

=2y^2+y^2-x^2-3x^2+3x

=3y^2-4x^2+3x

Answered by kruthisumeetha

1

its your answer ...,.,

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