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dude refer pic above please
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We can rewrite f(x) as ,
f(x) = x-1 for x≥1
= 1-x for x<1
LHL of f(x) at x=1 is 0.
RHL of f(x) at x=1 is 0.
So, f(x) is continuous at x=1.
RHD of f(x) at x=1 ,
lim
h→0={(1+h) - 1-(1-1)} /1+h-1
=>1+h-1-1+1/h
=>h/h
=>1
LHD of f(x) at x=1,
Lim
h→0={1-(1-h)-(1-1)}/1-h-1
=>1-1+h/-h
=>h/-h
=>-1
So, f(x) is not differentiable at x=1.
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