Question

Solve this question​

Answer 1

Answer:

Given: PQ is a tangent to the circle, angle AOB=100

To find: angle ABP = ?

Solution:

Now, considering the triangle formed AOB, we find that the sides are equal:

OA = OB ........(radius of the circle)

It indicates that the rest two angles are equal.

Let the angles be x( since both are same)

by angle sum property of a triangle, we get

100° + x + x = 180°

2x = 80°

x = 40°

Now, we know that PB is perpendicular to OB, as PQ is a tangent to circle and tangent is always perpendicular.

So, ang OBP = 90°

ang OBA + ang ABP = 90°

40 + ang ABP = 90°

ang ABP = 90° - 40°

ang ABP = 50°

Answer:

Therefore, angle ABP = 50°

Step-by-step explanation:

ang = angle