Solve this question
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2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=??
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Answers
Answered by
17
2(1) + 3(2)= 8
3(2) + 7(3) = 27
4(3) + 5(4) = 32
5(4) + 8(5) = 60
6(5) + 7(6) = 72
So,
7(6) + 8(7) = 42 + 56 = 98
______________________
Other way..
2 + 3 = 8 ( 2 × 3 + 2)
3 + 7 = 27 ( 3 × 7 + 3× 2)
4 + 5 = 32 ( 4 ×5 + 4 ×2)
5 + 8 = 60 ( 5 × 8 + 5 × 4)
6 + 7 = 72 ( 6× 7 + 6 × 5)
( First number × Second number + First number of same row × First number of preceding row)
So,
7 + 8 = ( 7 × 8 + 7× 6)
= 56 + 42
= 98
3(2) + 7(3) = 27
4(3) + 5(4) = 32
5(4) + 8(5) = 60
6(5) + 7(6) = 72
So,
7(6) + 8(7) = 42 + 56 = 98
______________________
Other way..
2 + 3 = 8 ( 2 × 3 + 2)
3 + 7 = 27 ( 3 × 7 + 3× 2)
4 + 5 = 32 ( 4 ×5 + 4 ×2)
5 + 8 = 60 ( 5 × 8 + 5 × 4)
6 + 7 = 72 ( 6× 7 + 6 × 5)
( First number × Second number + First number of same row × First number of preceding row)
So,
7 + 8 = ( 7 × 8 + 7× 6)
= 56 + 42
= 98
iamnitinpiyushp5kg82:
how did you get 3 from 7 in 2nd step as in all others you are subtracting 1
Answered by
10
Hey there..
Great question mate..
Here's your solution..
===================================
As per the question the pattern followed is —
2*3=6 , 2*(2–1)=2 , 6+2=8
In this initially multiply both numbers and multiply the first number by (first number-1).
Add both results
3*7=21 , 3*(3–1)=6, 21+6=27
4*5=20 , 4*(4–1)=12, 20+12=32
5*8=40 , 5*(5–1)=20, 40+20=60
6*7=42 , 6*(6–1)=30, 42+30=72
Similarly
7*8=56 ,7*(7–1)=42 , 56+42=98
The answer is 98.
===================================
HOPE IT HELPS
@Rêyaañ11
Great question mate..
Here's your solution..
===================================
As per the question the pattern followed is —
2*3=6 , 2*(2–1)=2 , 6+2=8
In this initially multiply both numbers and multiply the first number by (first number-1).
Add both results
3*7=21 , 3*(3–1)=6, 21+6=27
4*5=20 , 4*(4–1)=12, 20+12=32
5*8=40 , 5*(5–1)=20, 40+20=60
6*7=42 , 6*(6–1)=30, 42+30=72
Similarly
7*8=56 ,7*(7–1)=42 , 56+42=98
The answer is 98.
===================================
HOPE IT HELPS
@Rêyaañ11
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