Math, asked by suchismitabag00, 9 months ago

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Answered by vikash201097
1

Answer:

option b

Step-by-step explanation:

take x^2 common from both num and den and cancel it

(x-3)/(9-x^2)

denominator can be written as (3-x)*(3+x)

it will become -1/3+x

Answered by biligiri
1

Step-by-step explanation:

(x³ - 3x²) / (9x² - x⁴)

=> x²(x -3) / x²(9 - x²)

=> x²(x - 3) / x²(3+x)(3-x)

=> - x²(3 - x) / x²(3 + x)(3 - x)

=> - 1/(3 + x)

=> -1 / x + 3 option B

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