Math, asked by soumo42, 7 months ago

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Answered by Parulkapoor007
1

Answer:

204

Step-by-step explanation:

To find the smallest number , follow these steps :-

1) Subtract the remainders from the given numbers:

28-8 = 20

32 -12 = 20

Both of them give 20

2) Find the LCM of 28 and 32

28 = 2 × 2 × 7

32 = 2 × 2 × 2 × 2 × 2

LCM = 2 × 2 × 2 × 2 × 2 × 7 = 224

3) Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32 = LCM -20 = 224 - 20 = 204

204 is the answer !!!

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Answered by adarsh137999
0

Answer:

1.x/2=8

2.x/12=32

Step-by-step explanation:

x/2=8

x/2=12

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