Question

solve this question​

Answer 1

Answer :

3333.333m/s²

Explanation:

distance = 6 cm = 0.06 m

v= 20m/s

u=0m/s

v²=u²+2as

here u = 0

then v²=2as

20×20=2×a×0.06

a=-3333.3333m/s²

therefore deceleration = 3333.3333m/s²