Question

SOLVE THIS QUESTION ✍️✍️​

Answer 1

Answer:

-sqrt(5)/2

Step-by-step explanation:

plz check attachment for answer

Answer 2

Answer:

$\sqrt{1 - x {}^{2} } \frac{dy}{dx} + \sqrt{1 - y {}^{2} } = 0$

$= \frac{dy}{ \sqrt{1 - y {}^{2} } } + \frac{DX}{ \sqrt{1 - X62} } = 0$

Taking Integration ,

$= sin {}^{ - 1} y + sin \: {}^{ - 1} = c \: \: \: \: ......(1)$

$At \: X \: = \frac{1}{2} \: y \: = \frac{ \sqrt{3} }{2}$

$\frac{\pi}{3} + \frac{\pi}{6} = C$

$C = \frac{\pi}{2}$

Put in Equation ( 1 )

$sin \: { }^{ - 1} y = cos {}^{ - 1} x$

$y \frac{ \: (- 1)}{( \sqrt{2} )} = \frac{1}{ \sqrt{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ........ \: answer$