Question

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Answer 1

Given :-

Current in Galvanometer = ${I}_{G}$=0.006A

Current in Ammeter = I = 1.5 A

Resistance = 4990 Ohm

Potential Difference = V = 30 V

S = 2n/249

We are required to find the value of "n".

As we know that,

$(\dfrac{I -{I}_{G}}{{I}_{G}}) S = \dfrac{V}{{I}_{G}} - R$

(1.5 - 0.006)/0.006 × 2n/249 = 30/0.006 - 4990

1.494/0.006 × 2n/249 = 0.06/0.006

(2n × 1.494)/249 = 0.06

2n = 0.06 × 249/1.494

2n = 14.94/1.494

2n = 10

n = 5

Hence,

The value of n = 5 Answer......