Math, asked by ramdeep2441, 11 months ago

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Answered by pikachubisht67
1

Answer:

Step-by-step explanation:

(i) sum of sides = 90cm

p = 90cm/2 = 45cm

\sqrt[2]{p(p-a)(p-b)(p-c)} \\\sqrt[2]{45(45-20)(45-30)(45-40)} \\\\\sqrt[2]{45*25*15*5} \\\sqrt[2]{84375}\\ = 290.47

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Answered by aloksingh17801980
0

Answer:

i) sum of sides = 90cm

p = 90cm/2 = 45cm

\begin{gathered}\sqrt[2]{p(p-a)(p-b)(p-c)} \\\sqrt[2]{45(45-20)(45-30)(45-40)} \\\\\sqrt[2]{45*25*15*5} \\\sqrt[2]{84375}\\ = 290.47\end{gathered}

2

p(p−a)(p−b)(p−c)

2

45(45−20)(45−30)(45−40)

2

45∗25∗15∗5

2

84375

=290.47

do others similarly

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