Math, asked by uttkarsh5, 1 year ago

solve this question ,....

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Answered by birendrak1975
1
(i)Area of hexagon ABCDEF= Ar(ΔABF)+Ar(ΔEDC)+Ar(BFEC)
=1/2*BF*h+1/2*EC*h+(BC*BF)
=1/2*8*3+1/2*8*3+(6*8)
=12+12+48=72 cm^2
(ii)Area of hexagon ABCDEF=Ar(trap.ABCD)+Ar(trap.AFED)
=1/2*(12+6)*4*2
=18*4=72 cm^2
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