Question

solve this question​

Answer 1

Answer:

1

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Answer 2

Step-by-step explanation:

• ${64}^{x + 1} = \frac{64}{ {4}^{x} }$
• $= > \frac{64 {}^{x + 1} }{64} = {4}^{ - x}$
• $= > {64}^{x} = {4}^{ - x}$

$= > ({4}^{3} ) {}^{x} = {4}^{ - x}$

• $= > {4}^{3 x} = {4}^{ - x}$
• $= > 3x = - x$
• This is only possible when x = 0 . Hence the required answer is 0.
• I hope it will help you. Thank you