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Given,
three angles = 76°,54°,108°
And let the fourth angle be x°
We know that,
sum fo all angles in a quadrilateral = 360°
76°+54°+108°+ x = 360°
238° + x = 360°
x = 360° - 238°
x = 122°
Hence, the fourth angle = 122°
Answered by
3
Answer:
Angle D = 122°
Explanation:
GIVEN,
Angle A=76°
Angle B=54°
Angle C=108°
Angle D=?
To find;
Angle D=?
SOLUTION=>
=> sum of all angles of a quadrilateral=360° (angle sum property)
=> angle A+ angle B + angle C + angle D = 360°
=>76+54+108+ angle D =360°
=>238+ angle D =360°
=>angle D = 360°-238°
=>angle D = 122°
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