Question

solve this question

Answer 1

HELLO DEAR,
we know that:-
sin(90-theta)= cos (theta)
tan (90- theta)=cot theta
$= \frac{ \sin(25) }{ \cos(65) } + \frac{ \tan(23) }{ \cot(67) } \\ = > \frac{ \sin(90 - 65) }{ \cos(65) } + \frac{ \tan(90 - 67) }{ \cot(67) } \\ = > \frac{ \cos(65) }{ \cos(65) } + \frac{ \cot(67) }{ \cot(67) } \\ = > 1 + 1 = 2$
I HOPE ITS HELP YOU DEAR,
THANKS