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Answer:
k=6
Step-by-step explanation:
Discriminate =0
In this case,
Kx(x-2)+6=0
kx²-2kx+6=0
a=k, b= -2k, c= 6
So,
b²-4ac=0
putting the value
(-2k)²-4×k×6=0
4k²-24k=0
4k(k-6)=0 (As,4k becomes 0 while division)
k-6=0
k=6
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