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Given ABCD is rhombus .
DPR and CBR are straight lines.
∴ AD||CR
we need to Prove : DP.CR=DC.PR
In ∆ ADP and ∆ PCR
We have :
∠ APD = ∠ CPR
∠ ADP = ∠ PRC
∠ DAP = ∠ PCR
∴ ∆ ADP and ∆ PCR are similar triangle .
∴ we can write
AD/DP=CR/PR
Or AD.PR = DP.CR
∴ DC .PR = DP.CR Proved
hope it's clear to you...
DPR and CBR are straight lines.
∴ AD||CR
we need to Prove : DP.CR=DC.PR
In ∆ ADP and ∆ PCR
We have :
∠ APD = ∠ CPR
∠ ADP = ∠ PRC
∠ DAP = ∠ PCR
∴ ∆ ADP and ∆ PCR are similar triangle .
∴ we can write
AD/DP=CR/PR
Or AD.PR = DP.CR
∴ DC .PR = DP.CR Proved
hope it's clear to you...
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