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option 1 is correct answer
Step-by-step explanation:
In cyclic quadrilateral, sum of opposite angles is 180°.
7x+5°+3y-5°=180°
7x+3y-180°=0
7x+3y-180°=0[EQ.1]
4y+20°+4x°=180°
4x°+4y+20°-180°=0
4x+4y-160°=0
4(x+y-40°)=0
x+y-40°=0 [EQ.2]
From EQ. 2 we substitute the value of x=40-y and place it in EQ.1
7(40-y)+3y°=0
280-7y+3y-180°=0
100-4y=0
y=25°
now we substitute value of y=25 in EQ.2
x+25-40=0
x=15°
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