solve this question.
Attachments:
![](https://hi-static.z-dn.net/files/d6f/6ea6e424c7201febe240334625f4aaed.jpg)
Answers
Answered by
11
HELLO DEAR,
given that:-
Speed of water = 15km/hr
Distance travelled by upstream and downstream = 30 km
Time= 4hour 30 minutes = 4/2 hours
LET THE SPEED OF STREAM BE X
THEN,
(15+x)=speed of boat in downstream
so, time taken to travel 30km downstream = (30/15+x)
-----------------------AND------------------------
(15-x)=speed of boat in upstream
So, time taken to travel 30km upstream = (30/15-x)
we know that:-
TIME = distance / speed
![\frac{30}{15 + x} + \frac{30}{15 - x} = \frac{9}{2} \\ = > 30( \frac{15 - x + 15 + x}{(15 - x)(15 + x)} ) = \frac{9}{2} \\ = > \frac{30}{225 + 15x - 15x - {x}^{2} } = \frac{9}{2 \times 30} \\ = > \frac{30}{225 - {x}^{2} } = \frac{3}{20} \\ = > \frac{10}{225 - {x}^{2} } = \frac{1}{20} ...........mutiply \: both \: side \: by \: (\frac{1}{3} ) \\ = > 225 - {x}^{2} = 200 \\ = > {x}^{2} = 225 - 200 \\ = > {x}^{2} = 25 \\ = > x = \sqrt{25} \\ = > x = 5 \frac{30}{15 + x} + \frac{30}{15 - x} = \frac{9}{2} \\ = > 30( \frac{15 - x + 15 + x}{(15 - x)(15 + x)} ) = \frac{9}{2} \\ = > \frac{30}{225 + 15x - 15x - {x}^{2} } = \frac{9}{2 \times 30} \\ = > \frac{30}{225 - {x}^{2} } = \frac{3}{20} \\ = > \frac{10}{225 - {x}^{2} } = \frac{1}{20} ...........mutiply \: both \: side \: by \: (\frac{1}{3} ) \\ = > 225 - {x}^{2} = 200 \\ = > {x}^{2} = 225 - 200 \\ = > {x}^{2} = 25 \\ = > x = \sqrt{25} \\ = > x = 5](https://tex.z-dn.net/?f=+%5Cfrac%7B30%7D%7B15+%2B+x%7D++%2B++%5Cfrac%7B30%7D%7B15+-+x%7D++%3D++%5Cfrac%7B9%7D%7B2%7D++%5C%5C++%3D++%26gt%3B+30%28++%5Cfrac%7B15+-+x+%2B+15+%2B+x%7D%7B%2815+-+x%29%2815+%2B+x%29%7D+%29+%3D++%5Cfrac%7B9%7D%7B2%7D++%5C%5C++%3D++%26gt%3B+%5Cfrac%7B30%7D%7B225+%2B++15x+-+15x+-+%7Bx%7D%5E%7B2%7D+%7D++%3D++%5Cfrac%7B9%7D%7B2+%5Ctimes+30%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B30%7D%7B225+-++%7Bx%7D%5E%7B2%7D+%7D++%3D++%5Cfrac%7B3%7D%7B20%7D++%5C%5C++%3D++%26gt%3B++%5Cfrac%7B10%7D%7B225+-++%7Bx%7D%5E%7B2%7D+%7D++%3D++%5Cfrac%7B1%7D%7B20%7D+...........mutiply+%5C%3A+both+%5C%3A+side+%5C%3A+by+%5C%3A++%28%5Cfrac%7B1%7D%7B3%7D+%29+%5C%5C++%3D++%26gt%3B+225+-++%7Bx%7D%5E%7B2%7D++%3D+200+%5C%5C++%3D++%26gt%3B++%7Bx%7D%5E%7B2%7D++%3D+225+-+200+%5C%5C++%3D++%26gt%3B++%7Bx%7D%5E%7B2%7D++%3D+25+%5C%5C++%3D++%26gt%3B+x+%3D++%5Csqrt%7B25%7D++%5C%5C++%3D++%26gt%3B+x+%3D+5)
![{So, speed of the stream = 5 km/hr} {So, speed of the stream = 5 km/hr}](https://tex.z-dn.net/?f=%7BSo%2C+speed+of+the+stream+%3D+5+km%2Fhr%7D)
![I \: \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR,<br /> \: THANKS I \: \: \: HOPE \: \: ITS \: \: HELP \: \: YOU \: \: DEAR,<br /> \: THANKS](https://tex.z-dn.net/?f=I+%5C%3A++%5C%3A++%5C%3A++HOPE+%5C%3A++%5C%3A++ITS+%5C%3A++%5C%3A++HELP++%5C%3A++%5C%3A+YOU++%5C%3A++%5C%3A+DEAR%2C%3Cbr+%2F%3E+%5C%3A++THANKS)
given that:-
Speed of water = 15km/hr
Distance travelled by upstream and downstream = 30 km
Time= 4hour 30 minutes = 4/2 hours
LET THE SPEED OF STREAM BE X
THEN,
(15+x)=speed of boat in downstream
so, time taken to travel 30km downstream = (30/15+x)
-----------------------AND------------------------
(15-x)=speed of boat in upstream
So, time taken to travel 30km upstream = (30/15-x)
we know that:-
TIME = distance / speed
Similar questions