Question

solve this question.​

Answer 1

Answer:

x = 6,7

Step-by-step explanation:

${( {x}^{2} - 7x + 11)}^{ {x}^{2} - 13x + 42 } = 1$

$=> {( {x}^{2} - 7x + 11)}^{ {x}^{2} - 13x + 42 } = {( {x}^{2} - 7x + 11)}^{0}$

[as, p⁰ = 1]

$=> {x}^{2} - 13x + 42 = 0$

$=> {x }^{2} - 6x - 7x + 42 = 0$

$=> x(x - 6) - 7(x - 6) = 0$

$=> (x - 6)(x - 7) = 0$

=> x = 6 or, x = 7

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