Question

Solve this question. ​

Answer 1

GIVEN :

<QRS = 55°

<QSP = 75°

<P = 2<PQS

TO FIND :

<RQS = ?

<PQS = ?

SOLUTION :

In ∆RQS,

<QRS + <RQS = <QSP (by exterior angle property of a triangle)

55° + <RQS = 75°

<RQS = 75° - 55°

<RQS = 20°

<PSQ + RSQ = 180°

75° + <RSQ = 180°

<RSQ = 180° - 75°

<RSQ = 105°

<P + <PQS = <RSQ

2<PQS + <PQS = 105°

3<PQS = 105°

<PQS = 105°/3

<PQS = 35°

<P = 2<PQS

<P = 2(35°)

<P = 70°

SO, <RQS = 20°

<PQS = 35°

<P = 70°