Question

Solve this question...
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Answer 1

Answer:

Not injective but it is surjective

Step-by-step explanation:

f ( x) = 1 - 1 /x = [ x - 1 ] / x

{1 - x / x , 0 <x<1

{ x- 1 /x >1

f (x) is not injective

Range = codomain hence it is surjective

hope it help you

Answer 2

f ( x) = 1 - 1 /x = [ x - 1 ] / x

{1 - x / x , 0 <x<1

{ x- 1 /x >1

f (x) is not injective

Range = codomain hence it is surjective