Solve this question 2a^3+10a^2-28a
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Answer:
2a³+10a²-28a =2a(a+7)(a-2)
Step-by-step explanation:
2a³+10a²-28a
= 2a(a²+5a-14)
= 2a(a²+7a-2a-14)
= 2a[a(a+7)-2(a+7)]
= 2a(a+7)(a-2)
Therefore,
2a³+10a²-28a =2a(a+7)(a-2)
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