Question

solve this question 3 nd 4 ​

Answer 1

4 one answer is as follows

In traingle ADB,

BD=20,AB=12 therefore,AD=16

therefore,area of traingle ADB=1/2*base*height

1/2*12*16=96cm^2......(1)

and BDC is equilateral traingle

therefore area of traingle BDC=√3/4*sides^2

√3/4*20*20=1.73*5*20=173cm^2...(2)

from eq 1 and 2

area of quadrilateral ABCD=173+96=269cm^2

Hope it helps........

Answer 2

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