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let the distance travelled be x and the total fare be y
then, (standard fare fo 1 km) + ((total distance - 1 km)*(cost per km)) = total cost
5 + (x-1)3 = y
5 + 3x - 3 = y
2 + 3x = y
then, (standard fare fo 1 km) + ((total distance - 1 km)*(cost per km)) = total cost
5 + (x-1)3 = y
5 + 3x - 3 = y
2 + 3x = y
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