Question

Solve this Question............​

Answer 1

Answer:

No real value of n exists! Refer the Step-by-Step Explanation

Step-by-step explanation:

$\frac{3^{n}+3^{n-1}}{3^{n-1}-3^{n}} = \frac{2}{3}\\\\\frac{3^{n+1}+3^{n}}{3^{n-1}-3^{n}} = 2\\\\3^{n+1} + 3^{n} = 2\times3^{n-1} - 2\times3^{n}\\\\3^{n+1} + 3^{n} + 2\times3^{n} = 2 \times 3^{n-1}\\\\3^{n+1} + 3^{n}(1+2) = 2\times3^{n-1}\\\\3^{n+1} + 3^{n}\times3 = 2\times3^{n-1}\\\\3^{n+1}+3^{n+1} = 2 \times 3^{n-1}\\\\2 \times 3^{n+1} = 2\times 3^{n-1}\\\\3^{n+1} = 3^{n-1}\\\\n+1=n-1\\\\+1 = -1$

Thus no value of n is possible. No real value of n exists.