Math, asked by Hinanshu1, 1 year ago

solve this question.

Attachments:

Answers

Answered by sushant2505
1
Hi...☺

Here is your answer...✌

LHS

 =  \sqrt{ \sec ^{2}\alpha   +  \cosec  ^{2} \alpha } \\  \\  =   \sqrt{1 +  \tan ^{2}  \alpha  + 1 +  \cot ^{2}  \alpha  }   \\  \\  =  \sqrt{ \tan ^{2} \alpha  +   \cot^{2}   \alpha  + 2 }  \\  \\ =   \sqrt{ \tan ^{2} \alpha  +   \cot^{2}   \alpha  + 2 \times  { \tan \alpha }  \times  \cot \alpha }  \\  \\  =  \sqrt{ (\tan\alpha  +  \cot\alpha)^{2}  }  \\  \\  =  \tan\alpha   +  \cot\alpha

= RHS [ Proved ]
Similar questions