Question

solve this question....

Answer 1

1)
$= \frac{1}{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ = \frac{3 + \sqrt{2} }{9 - 2} = \frac{3 + \sqrt{2} }{7}$
put the value of √2
$= \frac{3 + 1.414}{7} \\ = \frac{4.414}{7} = 0.630 \: \: \: ans$
2)
$= \frac{2}{ \sqrt{3} - \sqrt{2} } \times ( \frac{ \sqrt{3 } + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } )$
$= \frac{2( \sqrt{3} + \sqrt{2} }{3 - 2} \\ = \frac{2( \sqrt{3} + \sqrt{2} )}{1}$
$= 2(1.732 + 1.414) \\ = 2 \times3 .146 = 6.292$
is the answer