Math, asked by mkkaushal123, 1 year ago

solve this question

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Answered by Anonymous
4
Heya!


Here is yr answer......


=> [(64)^-2]^-3 ÷ [{(-8)^2}^3]^2

=> -8^2×6 / -8^12

=> -8^12/-8^12

=> 1/1

=> 1


Hope it hlpz....
Answered by Anonymous
1
[{(-8)^2}^-2]^-3÷[{(-8)^2}^3]^2
(-8)^12÷(-8)^12
(-8)^12-12
(-8)^0
1
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