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Answered by
4
Heya!
Here is yr answer......
=> [(64)^-2]^-3 ÷ [{(-8)^2}^3]^2
=> -8^2×6 / -8^12
=> -8^12/-8^12
=> 1/1
=> 1
Hope it hlpz....
Here is yr answer......
=> [(64)^-2]^-3 ÷ [{(-8)^2}^3]^2
=> -8^2×6 / -8^12
=> -8^12/-8^12
=> 1/1
=> 1
Hope it hlpz....
Answered by
1
[{(-8)^2}^-2]^-3÷[{(-8)^2}^3]^2
(-8)^12÷(-8)^12
(-8)^12-12
(-8)^0
1
(-8)^12÷(-8)^12
(-8)^12-12
(-8)^0
1
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