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Answer 1

Answers

for a gas helium n=5mole

T=7+273=280k

a) a numbers of atoms of He is a 5 mole=

5×6.023×10²³atoms

=30.115×10²³atoms

=3.0115×10²⁴ He atoms

b)He atom is monoatomic so degree at freedom is3. so average kinite energy

=3/2Kbt per molecule

=3/2Kbt×number of helium

=3/2×1.38×10-²³×280×30.115×10²⁴

total E of 15 mole of He=17.4×10⁴J

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Answer 2

Explanation:

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We know that F = mg

= 1.5 × 9.8 = 14.7 N