Math, asked by shreyashsalunkhe9797, 6 hours ago

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Answered by BrainlyArnab
1

Plane x = 3 in equation (I)

Eq. (I) -

5 \times  \boxed{3} + 3y = 9  \\ \\  =  > 3y = 9 -  \boxed{15} \\  \\  =  > 3y =   \boxed{ - 6} \\  \\  =  > y =  \frac{ \boxed{ - 6 {}} }{3}  \\  \\  =  > y =  \boxed{ - 2}

hope it helps.

Answered by ald333999121
1

Answer:

2

Step-by-step explanation:

5×3+3y=9

3y=9-15

3y=6

y=6/3

y=2

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