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solve it your self
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Answer:
Amount of air remaining after 3rd pump=
(9a/16) (1/4)(9a/16)=27a/64
-
So the series is like OB/s 0
11:13 AM
no
it is not an arithmetic progression
Step-by-step explanation:
Let a be the amount of air initially
Amount of air remaining after 1st pump a
-fa/4)-3a/4
Amount of air remaining after 2nd
pump- (3a/4)-(1/4)(3a/4)=9a/16
Amount of air remaining after 3rd pump
(9a/16)-(1/4)(9a/16)-27a/64
So it is not Arithmetic Progression
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