Math, asked by ritiksingh10100, 1 month ago

solve this question ​

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Answers

Answered by anshkaundal095
0

Answer:

solve it your self

,

Answered by pmadhavsai30
1

Answer:

Amount of air remaining after 3rd pump=

(9a/16) (1/4)(9a/16)=27a/64

-

So the series is like OB/s 0

11:13 AM

no

it is not an arithmetic progression

Step-by-step explanation:

Let a be the amount of air initially

Amount of air remaining after 1st pump a

-fa/4)-3a/4

Amount of air remaining after 2nd

pump- (3a/4)-(1/4)(3a/4)=9a/16

Amount of air remaining after 3rd pump

(9a/16)-(1/4)(9a/16)-27a/64

So it is not Arithmetic Progression

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