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Answer:
(A+B+C)'s 1 day's work =
4
1
A's 1 day's work =
16
1
;
B's 1 day's work =
12
1
;
∴ C's 1 day's work =
4
1
−(
16
1
+
12
1
)=(
4
1
−
48
7
)=
48
5
So, C alone can do the work in
5
48
=9
5
3
days
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