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Explanation:we have to find the amount of Magnesium sulphate present in 135g of solid left evaporation of sea water.
you forgot to attach the table that shows the mass of various compound when 1 litre of sea water is evaporated lol. thankfully i have the question. so from table attached in answer,
we know that 6g of Magnesium sulphate present in 45g of salt gotten by evaporating of 1 litre of sea water.
∵ 6 g of Magnesium sulphate present in 45g of salt.
∴ magnesium sulphate present in 135g of salt = 6 × 135=810
now 810/45= 18g
18g of Magnesium sulphate present in 135g of solid left by evaporation of sea water :))
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