Question

solve this question
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Answer 1

Given: The sum of the digits of a two digit

number is 5, on adding 27 to the number its digits are reversed.

To find: The original number.

Solution:

• Now we have given that The sum of the digits of a two digit number is 5.

So, let the number be 10x + y. Then:

x + y = 5

x = 5-y.

• Now It is given that on adding 27 to the number its

digits are reversed.

10x + y +27= 10y + x

9x - 9y+27= 0 . Now putting (i), in above equation, we

9(5-y)-9y+27= 0

get: y = 72/18

45 - 9y - 9y+27= 0

72 = 18y

• Now putting y = 4 in equation (i), we get:

x = 5-y

x = 5-4

x = 1

. So the number is:

10x + y = 10(1) + 4 = 14