Question

solve this question

Answer 1

you can see your answer

Answer 2

$\text{Given that A,B,C are angles of a triangle. \\ We know that sum of all angles of triangle is 180} \\ \\ So, \\ \\ A + B + C = 180\degree \\ \\ C + A = 180 - B \\ \\ L.H.S \to \tan(\frac{C+A}{2}) \\ \\ = \tan(\frac{180-B}{2}) \\ \\ = \tan({90 - \frac{B}{2}) \\ \\ \\ \\ = \cot\frac{B}{2}$

Hence Proved

$Note: \ \ tan(90 - \theta) = cot\theta$