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In triangle ADC and triangle ABE
AB=AC(given)
angleA=angleA(common)
AD=AE(AB=AC and BD=CE)
therefore triangle ABE is congruent to triangle ACD
therefore, by cpct BE= CD
hence proved.
Hope it helps
AB=AC(given)
angleA=angleA(common)
AD=AE(AB=AC and BD=CE)
therefore triangle ABE is congruent to triangle ACD
therefore, by cpct BE= CD
hence proved.
Hope it helps
mayapushkar10:
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