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given: ∆abc is an equilateral triangle.
c is mid point of DE and DAC=EBC.
to prove : ∆DAC=~∆EBC.
proof: in ∆DAC and∆EBC
DC=EC. (given)
DAC=EBC (given)
AC=BC (sides of an equilateral triangle)
∆DAC=~∆EBC(SAS criterion)
hence proved.
c is mid point of DE and DAC=EBC.
to prove : ∆DAC=~∆EBC.
proof: in ∆DAC and∆EBC
DC=EC. (given)
DAC=EBC (given)
AC=BC (sides of an equilateral triangle)
∆DAC=~∆EBC(SAS criterion)
hence proved.
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