Solve this question 8 and 9
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2) sin 2theta =√3/2
sin 60 = √3/2
so theta = 30°
9) length of rod/ shadow
so √3/1 = 60°
sin 60 = √3/2
so theta = 30°
9) length of rod/ shadow
so √3/1 = 60°
knowlege34:
and 9 ?
thanks a lot
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