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Answered by KhushiPai
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Answer:

15(2x-3y)^2-4(4x-6y)-16

15(2x-3y)^2-4x2(2x-3y)-16 //Take 2 as common out of the second bracket and multiply it with the 4 outside the bracket.

15(2x-3y)^2-8(2x-3y)-16

Let (2x-3y)=a

15a^2-8a-16 // Substitute a into the equation in place of (2x-3y)

Solve the equation by the trinomial method (ax^2+bx+c)

15a^2-20a+12a-16

5a(3a-4)+4(3a-4)

(5a+4)(3a-4)

Now substitute (2x-3y) into the equation in place of a

{5(2x-3y)+4}{3(2x-3y)-4}

{10x-15y+4}{6x-9y-4}


Step-by-step explanation:


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