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We know that a right triangle have two acute angles.
and we also known that the sum of all angles of the triangle is 180°.
Let the other acute angle be X°
Then,one acute angle be (X-12)°=X°-12°
According to question,
X°+(X-12)°+90°=180°
=>X°+X°-12°+90°=180°
=>2x°+78°=180°
=>2x°=180°-78°
=>2x°= 102°
=>X°=
=51°
Hence, tge other acute angle is X°=51° and (X-12)°=X°-12°=51°-12°=39°
(iii)51°,39° is correct option.
and we also known that the sum of all angles of the triangle is 180°.
Let the other acute angle be X°
Then,one acute angle be (X-12)°=X°-12°
According to question,
X°+(X-12)°+90°=180°
=>X°+X°-12°+90°=180°
=>2x°+78°=180°
=>2x°=180°-78°
=>2x°= 102°
=>X°=
=51°
Hence, tge other acute angle is X°=51° and (X-12)°=X°-12°=51°-12°=39°
(iii)51°,39° is correct option.
daood85:
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