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The Factor Theorem tells us that (x-a) is a factor of f(x) if and only if f(a) = 0.
Here, our "(x-a)" candidate is:
g(x) = x + 1 = x - (-1)
We have
p(-1) = 2(-1)³ + (-1)² -2(-1) - 1
= -2 + 1 + 2 - 1
= 0
so YES, by the factor theorem
(x - (-1)) = x+1 = g(x)
is a factor of p(x).
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