Math, asked by rishiknsl02, 10 months ago

Solve this question.

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Answered by Jainprakhar003

0

Answer:

cos2(2x) =1-2sin2(2x)

=1-2(2sinx . cosx)2 { sin2x = 2sinx. cosx}

=1-2(4sin2x.cos2x)

=1-8sin2x.cos2x

LHS=RHS

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