Question

solve this question​

Answer 1

Heya

_____________________________

Find AC = ?

AC + CB = AB

AB = AC + 5.... equation ( i )

=>

in Trangle PAB

Tan ( 45° ) = AB/AP

=>

1 = AB/AP

=>

AB = AP

put value of AB in equation ( i )

=>

AP = AC + 5

In Trangle PAC

Tan ( 30 ) = AC/AP

=>

1/√3 = AC / AP

=>

1/√3 = AC / AC + 5

=>

AC + 5 = AC√3

AC = -5/ ( 1 - √3 )

=>

AC = -5 ( 1+√3 ) / -2

=>

AC = 5/2 ( 1 + √3 )


So, the height of tower is

2.5(√3+1)