Question

solve this question???

Answer 1

$( \frac{p}{q} )^{x - 5} = {( \frac{q}{p} )}^{x - 1} \\ \\ ({ \frac{p}{q} })^{x - 5} = ({q \div p})^{x - 1} \\ \\ ({ \frac{p}{q} })^{x - 5} = ({( \frac{1}{q} )^{ - 1} } \div p)^{x - 1} \\ \\ ({ \frac{p}{q} })^{x - 5} =({( \frac{1}{q} )^{ - 1} } \times p^{ - 1} )^{x - 1} \\ \\ ( \frac{p}{q} )^{x - 5} = (( \frac{1}{q} \times p)^{ - 1} )^{x - 1} \\ \\ ( \frac{p}{q} )^{x - 5} = (( \frac{p}{q} )^{ - 1} )^{x - 1} \\ \\ ( \frac{p}{q} )^{x - 5} = ( \frac{p}{q} )^{ - 1(x - 1)} \\ \\ ( \frac{p}{q} )^{x - 5} = ( \frac{p}{q} )^{ - x + 1} \\ \\ ( \frac{p}{q} )^{x - 5} = ( \frac{p}{q} )^{ 1 - x} \\ \\ \\ x - 5 = 1 - x \\ \\ x + x = 1 + 5 \\ \\ 2x = 6 \\ \\ x = \boxed{ \bold{3}}$

So the value of x is 3. Plz ask me if you have anu doubt on my answer.

Thank you...