Solve this question ( 892 ) square with algebraic identities
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Formula:(a+b+c)^2=(a)^2+(b)^2+(c)^2-(2)(ab+bc+c)
Solution
(800+90+2)^2= 800^2 + 90 ^2 + 2^2 -2( 800*90+90*2+800*2)
You can use this formula further to solve it.
Hope you found it helpful
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