Question

solve this question​

Answer 1

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Answer 2

Given : AB || CD and O is mid point of AD

To Prove :

1) ∆AOB ≈ ∆DOC

2) O is mid point of BC.

Proof :

In ∆ DOC and ∆ AOB

[A] - Angle CDO = Angle AOB

(Alternative interior angles as AB || CD)

[S] - OD = OA(O is mid point of AD)

[A] - Angle DOC = Angle AOB

[Vertically Opposite Angles]

Hence

∆ AOB ≈ ∆ DOC (ASA Congruency Rule )

Now

OC = OB [CPCT]

So O is mid point of BC

Hence Proved

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