Question

solve this question​

Answer 1

$\frac{sin \: x}{1 + cos \: x} + \frac{1 + cos \: x}{sin \: x} \\ = \frac{sin {}^{2} x \: + \: 1 + cos {}^{2}x \: + 2cosx }{sinx(1 + cos \: x)} \\ = \frac{2(1 + cosx)}{sinx(1 + cos \: x)} = \frac{2}{sinx}$

Actually the ques is wrong, we have to find the value of x I think