Question

solve this question above

Answer 1

Explanation:

Given

mass = 40kg

g = 10m/s^2

t > 500N then string break

T - mg = ma

a =( t - mg )/m

a = (500 - 400)/40

a = 100/40 = 2.5 m/s^2

since string break when t is grater then 500N so t= 500N taken .

Answer 2

It is given that,

The mass of the object (m) = 40 kg

Acceleration due to gravity(g) = 9.8 m/s²

Case:1

∴ Tension on the string = (m*g)

                                       =(40*9.8)

                                       = 392 newton

∴ Weight of the body is 392 newton

We know that, tension is equivalent to that of the negative weight or,

T = -W

∴ When the object is in contact with the surface then the tension on the string is 392 newton.

force = mass *acceleration

⇒392= 40*a

⇒ a = 392/40

⇒a = 9.8 m/s²

As per the question, the tension can't be greater than 500 newton.

∴ The force(f) on the string can't be more than 500 newton

We know that,

Case-2:

f = ma

⇒ 500 = 40*a

⇒ a = 500/40

⇒ a = 12.5 m/s²

But it is stated in the question that the force is acting against the force of gravity so there must be retardation.

So, for case (1) acceleration should be -9.8 m/s² and for case(2) the acceleration should be -12.5 m/s².

So, the retardation or acceleration for the mass might have to be between the range of -9.8 m/s² and -12.5 m/s².

So, according to the the question, the maximum acceleration for the mass can be_

(-9.8) - (-12.5)

= (-9.8+12.5)

= 2.7 m/s²

(Ans): The maximum acceleration for the mass can be 2.7 m/s².