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Given :- AC = BC
BA || CD
|_ DCA = 55
Solution :-
Since , BA || CD
So,
|_ BAC = |_DCA
as they are alternate interior angle!!
|_BAC = 55
In ∆ABC
AC = BC
and as we know that the angle opposite to the equal side are equal
|_ABC = |_BAC
|_ABC = 55
Now
Using ASP in ∆ABC
|_ABC + |_BAC + |_ACB = 180
55 + 55 + |_ACB = 180
110 + |_ACB = 180
|_ACB = 180 - 110
|_ ACB = 70
BA || CD
|_ DCA = 55
Solution :-
Since , BA || CD
So,
|_ BAC = |_DCA
as they are alternate interior angle!!
|_BAC = 55
In ∆ABC
AC = BC
and as we know that the angle opposite to the equal side are equal
|_ABC = |_BAC
|_ABC = 55
Now
Using ASP in ∆ABC
|_ABC + |_BAC + |_ACB = 180
55 + 55 + |_ACB = 180
110 + |_ACB = 180
|_ACB = 180 - 110
|_ ACB = 70
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